Alternatively, as listed in Table 4, default power allocation may be used, and each modulation scheme combination is corresponding to one power allocation ratio. In this case, only four bits are required to represent all combination statuses of modulation schemes currently used by the second user equipment and the first user equipment, the power allocation ratios, and the layer pairing.
It is assumed that the second user equipment is limited to Z modulation schemes, each modulation scheme combination has Y power allocation levels, and there are two layer pairing relationships (one layer of the near-end UE+one layer of the far-end UE, and two layers of the near-end UE+one layer of far-end UE 1+one layer of far-end UE 2). The far-end UE may use a 16 QAM modulation scheme. In this case, a total quantity V of required bits is: V=┌l(fā)og2(1+max(Lfar×Y16 QAM,far,1)+Z×L×max(YZ,QPSK,far,Y16 QAM,far))┐??(1)