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Semi-orthogonal transmission-based communication method and device

專利號(hào)
US10588118B2
公開日期
2020-03-10
申請(qǐng)人
Huawei Technologies Co., Ltd.(CN Shenzhen)
發(fā)明人
Zhiheng Guo; Hai Wu; Xingqing Cheng
IPC分類
H04W72/04; H04B7/0452
技術(shù)領(lǐng)域
equipment,user,downlink,allocation,pairing,modulation,scheme,olsm,power,signal
地域: Shenzhen

摘要

A semi-orthogonal transmission-based communication method and a device, with the method including receiving, by first user equipment, downlink control information sent by a base station, where the downlink control information includes at least one of downlink control parameter of the first user equipment, pairing layer information of the first user equipment, modulation scheme information of second user equipment, power allocation information, an identifier of the first user equipment, or pairing information, and receiving, by the first user equipment, a data signal of an associated user equipment group that is sent by the base station, by the first user equipment, the data signal of the first user equipment according to the downlink control information and the data signal of the associated user equipment group.

說明書

0.2 0.8 1 16QAM + QPSK 64QAM 0.2381 0.7619 2 64QAM + QPSK 256QAM 0.2471 0.7529 3 16QAM + 16QAM 256QAM 0.0588 0.9412

Alternatively, as listed in Table 4, default power allocation may be used, and each modulation scheme combination is corresponding to one power allocation ratio. In this case, only four bits are required to represent all combination statuses of modulation schemes currently used by the second user equipment and the first user equipment, the power allocation ratios, and the layer pairing.

It is assumed that the second user equipment is limited to Z modulation schemes, each modulation scheme combination has Y power allocation levels, and there are two layer pairing relationships (one layer of the near-end UE+one layer of the far-end UE, and two layers of the near-end UE+one layer of far-end UE 1+one layer of far-end UE 2). The far-end UE may use a 16 QAM modulation scheme. In this case, a total quantity V of required bits is:
V=┌l(fā)og2(1+max(Lfar×Y16 QAM,far,1)+Z×L×max(YZ,QPSK,far,Y16 QAM,far))┐??(1)

權(quán)利要求

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